A thermodynamic system is taken from an original state $D$ to an intermediate state $E$ by the linear process shown in the figure. Its volume is then reduced to the original volume from $E$ to $F$ by an isobaric process. The total work done by the gas from $D$ to $E$ to $F$ will be

Question

Aicharya · Accepted Answer

Total work done by the gas from D to E to F = Area of &#8710; D E F Work done during the process D E is W DE = 1 2 600 + 300 5 - 2 &#160; J = 1350 &#160; J Work done during the process E F is W EF = - 300 &#215; 3 = - 900 &#160; J W DEF = W DE + W EF = 450 &#160; J

A thermodynamic system is taken from an original state D to an intermediate state E by the linear process…

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