A thermodynamic system is taken from an initial state i with internal energy U i = 100 J to the final state…

A thermodynamic system is taken from an initial state i with internal energy Ui =100 J to the final state f along two different paths iaf and ibf, as schematically shown in the figure. The work done by the system along the paths af, ib and bf are waf= 200 J, Wib = 50 J and Wbf = 100 J respectively. The heat supplied to the system along the path iaf, ib and bf are iaf ib Qiaf, Qib and Qbf respectively. If the internal energy of the system in the state b is Ub=200 J and Qiaf=500 J , the ratio QbfQib  is

Solution

Process iaf
Process W(in Joule) U (in Joule) Q(in Joule)i
ia 0
af 200
Net 300 200 500

Uf=400 Joule
Process ibf
Process W(in Joule) U (in Joule) Q(in Joule)i
ib 100 50 150
Bf 200 100 300
Net 300 150 450

QbfQib=300150=2 `

Asked in: JEE Advanced 2014 (Paper 1)

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