A tally bar table shows the number of cars passing a junction each hour: $8$ AM-$10$, $9$ AM-$15$, $10$…
A tally bar table shows the number of cars passing a junction each hour: $8$ AM-$10$, $9$ AM-$15$, $10$ AM-$22$, $11$ AM-$18$. The frequency of the busiest hour is:
$10$
$15$
$18$
$22$
Solution
Busiest hour has the maximum frequency: $\max(10,15,22,18) = 22$ at $10$ AM.