A system of two blocks of masses m = 2   kg and M = 8   kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocks is 0 . 5 . The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be g…

Question

A system of two blocks of masses m = 2 &#160; kg and M = 8 &#160; kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocks is 0 . 5 . The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be g = 9 . 8 &#160; m &#160; s - 2

Aicharya · Accepted Answer

Maximum acceleration of the upper block will be,

$a_{m a x} = μ g = 0.5 \times 9.8 = 4.9 m s^{- 2}$

Therefore, maximum force that can be applied on the lower block is,

$F_{\max} = (2 + 8) \times 4.9 = 49 N$

A system of two blocks of masses m = 2   kg and M = 8   kg is placed on a smooth table as shown in…

Solution

A system of two blocks of masses m = 2 &#160; kg and M = 8 &#160; kg is placed on a smooth table as shown in…

Solution

A system of two blocks of masses m = 2 kg and M = 8 kg is placed on a smooth table as shown in…