A system is taken from state - A to state - B along two different paths. The heat absorbed and work done by the system along these two paths are Q 1 , Q 2 and W 1 , W 2 respectively, then

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Aicharya · Accepted Answer

Internal energy for a thermodynamic process is a point function, it does not depend upon the path or process it only depends upon the initial and final state of the process.

Therefore, if two different processes have the same initial and final state then the internal energy of system will be same for both processes.

Using the first law of thermodynamics for a finite process. $Q = W + ∆ U$

For path $1$ the first law can be written as, $Q_{1} = W_{1} + ∆ U \dots \dots (1)$

For path $2$ the first law is, $Q_{2} = W_{2} + ∆ U \dots \dots (2)$

From equation (1) and (2)

$Q_{1} - W_{1} = Q_{2} - W_{2}$

A system is taken from state - A to state - B along two different paths. The heat absorbed and work done by…

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