A system consists of two identical spheres each of mass 1 . 5   kg and radius 50   cm at the ends…

1. $1.905\times {10}^5 \mathrm{kg} {\mathrm{m}}^2$
2. $18.75 \mathrm{kg} {\mathrm{m}}^2$
3. $19.05 \mathrm{kg} {\mathrm{m}}^2$
4. $1.875\times {10}^5 \mathrm{kg} {\mathrm{m}}^2$

Solution

$\left.I=\left(\frac{2}{5}M{R}^2+M{x}^2\right)\times 2=\left[\frac{2}{5}\times 1.5\times {\left(0.5\right)}^2+1.5\times {\left(2.5\right)}^2\right)\right]\times 2=[0.15+9.375]\times 2=19.05{\mathrm{kgm}}^2$

Asked in: JEE Main 2021 (31 Aug Shift 2)

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