A system changes from the state $\left(P_{1}, V_{1}ight)$ to $\left(P_{2}ight.$ $\mathrm{V}_{2}$ ) as shown…
- $7.5 \times 10^{5}$ joule
- $7.5 \times 10^{5}$ erg
- $12 \times 10^{5}$ joule
- $6 \times 10^{5}$ joule
Solution
$=4 \times 1 \times 10^{5}+1 / 2 \times 4 \times 10^{5} \times 4$
$=12 \times 10^{5}$ Joule
~Asked in: JEE-TOPICTESTS-CHEMISTRY