A swimming pool has depth of 3 meters. The pressure at the bottom of the pool due to water alone is (Density…
A swimming pool has depth of 3 meters. The pressure at the bottom of the pool due to water alone is (Density of water is $1000 \mathrm{~kg} \mathrm{~m}^{-3}$, Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
$10^4 \mathrm{~Pa}$
$3 \times 10^3 \mathrm{~Pa}$
$29 \times 10^3 \mathrm{~Pa}$
$30 \times 10^3 \mathrm{~Pa}$
Solution
Depth, $\mathrm{h}=3 \mathrm{~m}$
density, $\rho=10^3 \mathrm{~kg} / \mathrm{m}^3$
Acceleration due to gravity, $g=10 \mathrm{~m} / \mathrm{s}^2$
Pressure at bottom is given by
$\begin{aligned} & \mathrm{P}=\rho \mathrm{gh} \\ & \mathrm{P}=10^3 \times 10 \times 3 \\ & \mathrm{P}=30 \times 10^3 \mathrm{~Pa}\end{aligned}$