A surface has the area vector $\vec{A}=(2 \hat{i}+3 \hat{j}) m^{2} .$ Then what is the flux (in $\mathrm{V}-\mathrm{m}$ ) of an electric field through it if the field is $\vec{E}=4 \hat{i} \frac{V}{m} ?$

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Aicharya · Accepted Answer

$\phi=\vec{E} \cdot \vec{A}=4 \hat{i} .(2 \hat{i}+3 \hat{j})=8 \mathrm{~V}-\mathrm{m}$ ^

A surface has the area vector $\vec{A}=(2 \hat{i}+3 \hat{j}) m^{2} .$ Then what is the flux (in…

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