A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the…

A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is
  1. $196$
  2. $140$
  3. $168$
  4. $176$

Solution

Total number of questions $=13$ Now of questions to be selected $=10$ Restriction - At least 4 from first 5 questions are to be selected. Case I If exactly 4 out of first 5 questions are selected. Number of ways of selecting 4 questions from 5 questions $={ }^5 C_4=5$ Remaining $10-4=6$ questions are selected from last $13-5=8$ questions in ${ }^8 C_6$ ways - $\therefore$ Number of ways $=5 \times{ }^8 C_6=140$ Case II If exactly 5 out of first 5 questions are selected. Number of ways of selecting 5 out of 5 questions $={ }^5 C_5=1$ Remaining $10-5=5$ questions are selected from last $13-5=8$ questions in ${ }^8 C_5$ ways. $\therefore$ Number of ways $=1 \times{ }^8 C_5=56$ $\therefore$ Total number of ways $=140+56=196$

Asked in: AP EAMCET 2022 (08 Jul Shift 2)

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