A string of mass $0 \cdot 1 \mathrm{~kg}$ is under a tension $1 \cdot 6 \mathrm{~N}$. The length of the…

A string of mass $0 \cdot 1 \mathrm{~kg}$ is under a tension $1 \cdot 6 \mathrm{~N}$. The length of the string is $1 \mathrm{~m}$. A transverse wave starts from one end of the string. The time taken by the wave to reach the other end is
  1. $0.30 \mathrm{~s}$.
  2. $0.50 \mathrm{~s}$.
  3. $0.25 \mathrm{~s}$
  4. $0.75 \mathrm{~s}$

Solution

Mass of string $=0.1 \mathrm{lgg}$ Tension $T=1.6 \mathrm{~N}$ Length $\quad \ell=1 \mathrm{~m}$ Man per unit length $\mu=\frac{m}{1}=\frac{0.1}{1}=0.1 \mathrm{~kg} / \mathrm{m}$ The velocity $(v)$ of the transverse wave in the string is given by the relation $\begin{aligned} V &=\sqrt{\frac{T}{4}} \\ &=\sqrt{\frac{1.6}{0.1}} \\ &=4 \mathrm{~m} / \mathrm{s} \end{aligned}$ Time taken $T=\ell / V=1 / 4=0.25 \sec$

Asked in: MHT CET 2020 (13 Oct Shift 2)

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