
A string of length ' $\ell$ ' fixed at one end carries a mass 'm' at the other end. The string makes…

- $36 \mathrm{~m} \ell$
- $3 \mathrm{~m} \boldsymbol{\ell}$
- $9 \mathrm{~m} \ell$
- $18 \mathrm{~m} \ell$
Solution
$\omega=\frac{3}{\pi} \varepsilon p s=6 \mathrm{rad} / 8 .$
$T=m \omega^{2} \ell$
$=36 m .$Asked in: MHT CET 2020 (13 Oct Shift 2)