A stretched string is fixed at both ends. It is made to vibrate so that the total number of nodes formed in…

A stretched string is fixed at both ends. It is made to vibrate so that the total number of nodes formed in it is ' $x$ '. The length of the string in terms of the wavelength of waves formed in it is ( $\lambda=$ wavelength)
  1. $\frac{\mathrm{X} \lambda}{2}$
  2. $\left(\mathrm{X}+\frac{1}{2}\right) \frac{\lambda}{2}$
  3. $(X+1) \frac{\lambda}{2}$
  4. $(\mathrm{X}-1) \frac{\lambda}{2}$

Solution

For a string with fixed ends, the length is determined by the number of nodes (x). The length in terms of wavelength is given by $(X+1) \frac{\lambda}{2}$.

Asked in: MHT CET 2024 (02 May Shift 2)

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