A straight wire of length $0 \cdot 5 \mathrm{~m}$ and carrying current of $1 \cdot 2 \mathrm{~A}$ is placed…
A straight wire of length $0 \cdot 5 \mathrm{~m}$ and carrying current of $1 \cdot 2 \mathrm{~A}$ is placed in a uniform magnetic field of induction $2 \mathrm{~T}$. The magnetic field is perpendicular to the length of the wire. What is the force acting on the wire? $\left[\sin 90^{\circ}=1\right]$
$2 \cdot 0 \mathrm{~N}$
$2 \cdot 4 \mathrm{~N}$
$1 \cdot 2 \mathrm{~N}$
$3 \cdot 0 \mathrm{~N}$
Solution
When a current-carrying wire is placed in a magnetic field perpendicular to the length of the wire, the force acting on the wire is given by the formula:
$F=B I L$
Where:
- $F$ is the force on the wire,
- $B$ is the magnetic field induction,
- $I$ is the current,
- $L$ is the length of the wire.
Since the magnetic field is perpendicular to the wire, the force is maximized, and the force acting on the wire is directly proportional to the magnetic field, current, and wire length.