A straight line $L$ cuts both the lines $5 x-y-4=0$ and $3 x+4 y-4=0$. The segment of $L$ between the two…

A straight line $L$ cuts both the lines $5 x-y-4=0$ and $3 x+4 y-4=0$. The segment of $L$ between the two lines is bisected at the point $(1,5)$. The equation of $L$ is
  1. $63 x-32 y+62=0$
  2. $36 x-53 y-72=0$
  3. $38 x-65 y-45=0$
  4. $83 x-35 y+92=0$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 2)

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