A straight conductor of length $0.6 \mathrm{~m}$ is moved with a speed of $10 \mathrm{~ms}^{-1}$…
A straight conductor of length $0.6 \mathrm{~m}$ is moved with a speed of $10 \mathrm{~ms}^{-1}$ perpendicular to magnetic field of induction 1.2 weber $\mathrm{m}^{-2}$. The induced e.m.f. across the conductor is
$6 \mathrm{~V}$
$7.2 \mathrm{~V}$
$0.72 \mathrm{~V}$
$12 \mathrm{~V}$
Solution
The induced emf is given by
$\mathrm{E}=\mathrm{B} \ell \mathrm{v}=1.2 \times 0.6 \times 10=7.2 \mathrm{~V}$