A stone tied to 180   cm long string at its end is making 28 revolutions in horizontal circle in every minute. The magnitude of acceleration of stone is 1936 x   m   s - 2 . The value of x ______. [Take π = 22 7 ]

Question

A stone tied to 180 &#160; cm long string at its end is making 28 revolutions in horizontal circle in every minute. The magnitude of acceleration of stone is 1936 x &#160; m &#160; s - 2 . The value of x ______. [Take &#960; = 22 7 ]

Aicharya · Accepted Answer

Angular velocity, &#969; = 28 &#215; 2 &#960; 60 &#160; rad &#160; s - 1 . Required centripetal acceleration is given by, a = &#969; 2 R = 56 60 &#215; 22 7 2 &#215; 1 . 8 = ( 44 ) 2 225 &#215; 1 . 8 = 1936 125 Hence, required x = 125 .

A stone tied to 180   cm long string at its end is making 28 revolutions in horizontal circle in every…

Solution

A stone tied to 180 &#160; cm long string at its end is making 28 revolutions in horizontal circle in every…

Solution

A stone tied to 180 cm long string at its end is making 28 revolutions in horizontal circle in every…