A stone is hung in air from a wire which is stretched over a sonometer. The bridges of the sonometer are…

A stone is hung in air from a wire which is stretched over a sonometer. The bridges of the sonometer are $L\text{ cm}$ apart when the wire is in unison with a tuning fork of frequency $N$. When the stone is completely immersed in water, the length between the bridges is $l\text{ cm}$. For re-establishing unison, the specific gravity of the material of the stone is
  1. $\frac{L^2}{L^2 + l^2}$
  2. $\frac{L^2 - l^2}{L^2}$
  3. $\frac{L^2}{L^2 - l^2}$
  4. $\frac{L^2 + l^2}{L^2}$

Solution

Frequency of vibration stretched string, $n = \frac{1}{2l} \sqrt{\frac{T}{m}}$ When the stone is completely immersed in water, length changes but frequency does not change. $l \propto \sqrt{T} \Rightarrow \frac{L}{l} = \sqrt{\frac{V\rho g}{V(\rho - 1)g}}$ $\Rightarrow \frac{L}{l} = \sqrt{\frac{\rho}{\rho - 1}} \Rightarrow \rho = \frac{L^2}{L^2 - l^2}$

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