A stone falls freely under gravity. It covers distances $h_1, h_2$ and $h_3$ in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between $h_1, h_2$ and $h_3$ is

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Aicharya · Accepted Answer

$\begin{aligned} & h_1=\frac{1}{2} g t^2=\frac{1}{2} \times 10 \times 5^2=125 \ & h_2=\frac{1}{2} \times 10 \times 10^2-\frac{1}{2} \times 10 \times 5^2=375 \ & h_3=\frac{1}{2} \times 10 \times 15^2-\frac{1}{2} \times 10 \times 10^2=625 \end{aligned}$ Hence $h_1=\frac{h_2}{3}=\frac{h_3}{5}$

A stone falls freely under gravity. It covers distances $h_1, h_2$ and $h_3$ in the first 5 seconds, the…

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