A step down transformer is used to reduce the main supply from ' $V_1$ ' volt to ' $V_2$ ' volt. The primary…

A step down transformer is used to reduce the main supply from ' $V_1$ ' volt to ' $V_2$ ' volt. The primary coil draws a current ' $I_1$ ' A and the secondary coil draws ' $I_2$ ' A. $\left(I_1 < I_2\right)$. The ratio of input power to output power is
  1. $\frac{\mathrm{V}_1 \mathrm{~V}_2}{\mathrm{I}_1 \mathrm{I}_2}$
  2. $\frac{\mathrm{I}_1 \mathrm{~V}_1}{\mathrm{I}_2 \mathrm{~V}_2}$
  3. $\frac{\mathrm{I}_1 \mathrm{I}_2}{\mathrm{~V}_1 \mathrm{~V}_2}$
  4. $\frac{\mathrm{V}_1 \mathrm{I}_2}{\mathrm{~V}_2 \mathrm{I}_1}$

Solution

$\begin{aligned} & \text { Input power }=\mathrm{I}_1 \mathrm{~V}_1 \\ & \text { Output power }=\mathrm{I}_2 \mathrm{~V}_2\end{aligned}$

Asked in: MHT CET 2021 (22 Sep Shift 2)

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