A steel wire of length \(20 \mathrm{~cm}\) and area of crosssection \(1 \mathrm{~mm}^2\) is tied rigidly at…

A steel wire of length \(20 \mathrm{~cm}\) and area of crosssection \(1 \mathrm{~mm}^2\) is tied rigidly at both the ends. When the temperature of the wire is changed from \(40^{\circ} \mathrm{C}\) to \(20^{\circ} \mathrm{C}\), find the change in its tension. Given, the coefficient of linear expansion for steel is \(1.1 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}\) and Young's modulus of steel is \(2.0 \times 10^{11} \mathrm{Nm}^{-2}\).
  1. \(22 \mathrm{~N}\)
  2. \(44 \mathrm{~N}\)
  3. \(16 \mathrm{~N}\)
  4. \(8 \mathrm{~N}\)

Solution

Given, Young's modulus of steel wire, \(Y=2 \times 10^{11} \mathrm{Nm}^{-2}\) Length of wire, \(l=20 \mathrm{~cm}=0.2 \mathrm{~m}\) Area of cross-section, \(A=1 \mathrm{~mm}^2=10^{-6} \mathrm{~m}^2\) Change in temperature of wire, \(\begin{aligned} \Delta t & =(40-20)^{\circ} \mathrm{C} \\ & =20^{\circ} \mathrm{C} \\ \alpha & =1.1 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1} \end{aligned}\) \(\therefore\) Change in tension in the steel wire, \(\begin{aligned} T & =Y A \alpha \Delta t \\ & =2 \times 10^{11} \times 10^{-6} \times 1.1 \times 10^{-5} \times 20 \\ & =44 \mathrm{~N} \end{aligned}\)

Asked in: AP EAMCET 2020 (21 Sep Shift 1)

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