A steel block of 10   kg rests on a horizontal floor as shown. When three iron cylinders are placed on…

A steel block of 10 kg rests on a horizontal floor as shown. When three iron cylinders are placed on it as shown, the block and cylinders go down with an acceleration 0.2 m s-2. The normal reaction R' by the floor if mass of the iron cylinders are equal and of 20 kg each is in N,

[Take g=10 m s-2 and μs=0.2

  1. 716
  2. 686
  3. 714
  4. 684

Solution

Writing force equation in vertical direction, 
Mg-N=Ma
70 g-N=70×0.2
N=70[ g-0.2]=70×9.8
N=686 newton
Note: Since there is no compressive normal from the sides, hence friction will not act.
Hence option 2.

Asked in: JEE Main 2021 (20 Jul Shift 1)

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