A steam engine intakes 50   g of steam at 100 ° C per minute and cools it down to 20 ° C . If latent heat of vaporization of steam is 540   cal   g - 1 , then the heat rejected by the steam engine per minute is _____ × 10 3   cal (Given : specific heat capacity…

Question

A steam engine intakes 50 &#160; g of steam at 100 &#176; C per minute and cools it down to 20 &#176; C . If latent heat of vaporization of steam is 540 &#160; cal &#160; g - 1 , then the heat rejected by the steam engine per minute is _____ &#215; 10 3 &#160; cal (Given : specific heat capacity of water : 1 &#160; cal &#160; g - 1 C &#8728; - 1 )

Aicharya · Accepted Answer

Heat rejected by the steam engine per minute will be equal to latent heat per minute plus heat rejected by the water to cool down.

$\frac{∆ H}{∆ t} = \frac{∆ m}{∆ t} L + \frac{∆ m}{∆ t} s ∆ T \Rightarrow \frac{∆ H}{∆ t} = 50 \times 540 + 50 \times 1 \times 80 = 31000 cal \min^{- 1} = 31 \times 10^{3} cal \min^{- 1}$

A steam engine intakes 50   g of steam at 100 ° C per minute and cools it down to 20 ° C . If…

Solution

A steam engine intakes 50 &#160; g of steam at 100 &#176; C per minute and cools it down to 20 &#176; C . If…

Solution

A steam engine intakes 50 g of steam at 100 ° C per minute and cools it down to 20 ° C . If…