A steady current of $1.5 \mathrm{amp}$ flows through a copper voltameter for 10 minutes. If the…
A steady current of $1.5 \mathrm{amp}$ flows through a copper voltameter for 10 minutes. If the electrochemical equivalent of copper is 30 $\times 10^{-5} \mathrm{~g}$ coulomb $^{-1}$, the mass of copper deposited on the electrode will be.
$0.50 \mathrm{~g}$
$0.67 \mathrm{~g}$
$0.27 \mathrm{~g}$
$0.40 \mathrm{~g}$.
Solution
Given that $\mathrm{I}=1.5 \mathrm{~A} t=10 \mathrm{~mm}=600$ sec
and $z=30 \times 10^{-5} \mathrm{~g} \mathrm{~coulomb}^{-1}$
According to faraday first law of electrolysis
$\begin{aligned}
& m=Z I T=30 \times 10^{-5} \times 1.5 \times 600= \\
& 0.27 \mathrm{~g}
\end{aligned}$
