A stationery wave is represented by $y=12 \cos \left(\frac{\pi}{6} x\right) \sin (8 \pi t)$, where $x \& y$…
- 12 cm
- 10 cm
- 6 cm
- 2 cm
Solution
Comparing this equation with standard stationary wave equation, $y=2 A \sin \left(\frac{2 \pi x}{\lambda}\right) \cdot \cos \left(\frac{2 \pi}{\lambda} t\right)$ $\begin{aligned} & \text { We get, } \\ & \frac{2 \pi}{\lambda}=\frac{\pi}{6} \\ & \therefore \quad \lambda=12 \mathrm{~cm} \end{aligned}$ $\therefore \quad$ Distance between two successive antinodes $=\frac{\lambda}{2}=6 \mathrm{~cm}$
Asked in: MHT CET 2024 (04 May Shift 2)