A square shaped hole of side   l =   a 2 is carved out at a distance d = a 2 from the centre '…

A square shaped hole of side l= a2 is carved out at a distance  d=a2 from the centre 'O' of a uniform circular disk of radius a. If the distance of the centre of mass of the remaining portion from O is -ax, value of X (to the nearest integer) is :

  

Solution

Xa=A·X-A·X1A-A1=πa2×0-a24×a2πa2-a24
=-a3/8π-14a2=-a2(4π-1)=-a8π-2=-a23
x=23

Asked in: JEE Main 2020 (02 Sep Shift 2)

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