A square loop, carrying a steady current $I$, is placed in a horizontal plane near a long straight conductor…

A square loop, carrying a steady current $I$, is placed in a horizontal plane near a long straight conductor carrying a steady current $I_1$ at a distance $d$ from the conductor as shown in figure. The loop will experience

1. a net repulsive force away from the conductor
2. a net torque acting upward perpendicular to the horizontal plane
3. a net torque acting downward normal to the horizontal plane
4. a net attractive force towards the conductor

Solution

$\begin{aligned} & \mathbf{F}_2=-\mathbf{F}_4 \\ & \mathbf{F}_1=\frac{\mu_0 I_1 I l}{2 \pi d} \\ & \mathbf{F}_2=\frac{\mu_0 I_1 I l}{2 \pi(d+l)} \\ & \mathbf{F}_1 > \mathbf{F}_3 \\ & F_{\text {net }}=F_1-F_3 \end{aligned}$ So, wire atrract loop. /

Asked in: NEET 2011 (Mains)

Practice more Magnetic Fields due to Electric Current questions on Aicharya