A square Lamina OABC of length 10 cm is pivoted at 'O'. Forces act at Lamina as shown in figure. If Lamina…

A square Lamina OABC of length 10 cm is pivoted at 'O'. Forces act at Lamina as shown in figure. If Lamina remains stationary, then the magnitude of F is :

1. 20 N
2. 0 (zero)
3. 10 N
4. $10 \sqrt{2} \mathrm{~N}$

Solution

Since the lamina is equilibrium.
$\therefore \mathrm{F}_{\mathrm{net}}=0 \& \tau_{\mathrm{net}}=0$

$\mathrm{T}_{\mathrm{o}}=10 \ell-\mathrm{F} \ell \Rightarrow \mathrm{F}=10 \mathrm{~N}$

Asked in: JEE Main 2025 (02 Apr Shift 1)

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