A square is formed by the lines \(x=0, y=0\), \(x=1, y=1\). Then, the equations of its diagonals will be
- \(y=x, x+y=2\)
- \(2 y=x, x+y=\frac{1}{2}\)
- \(y=x, x+y=1\)
- \(y=2 x, x+y=\frac{1}{4}\)
Solution

\(\begin{aligned} \quad y & =\left(\frac{1-0}{1-0}\right) x \\ \Rightarrow \quad(y & =x) \end{aligned}\) Equation of \(A C\) \(\Rightarrow \quad \begin{aligned} y-0 & =-1(x-1) \\ \Rightarrow \quad y & =-x+1 \Rightarrow x+y=1 \end{aligned}\)
Asked in: AP EAMCET 2020 (17 Sep Shift 1)