A square is also a rhombus. The diagonal of a square of side $10$ cm is $10\sqrt{2}$ cm. Verify the rhombus…
A square is also a rhombus. The diagonal of a square of side $10$ cm is $10\sqrt{2}$ cm. Verify the rhombus area formula on this square.
- $50 \text{ cm}^{2}$
- $100 \text{ cm}^{2}$
- $200 \text{ cm}^{2}$
- $25 \text{ cm}^{2}$
Solution
Both diagonals are equal $= 10\sqrt{2}$. Area $= \dfrac{1}{2}(10\sqrt{2})(10\sqrt{2}) = \dfrac{1}{2}\cdot 200 = 100 \text{ cm}^{2}$, matching $a^{2} = 100$.
Asked in: IMO
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