A square garden of side $a$ has a square pond of side $b$ ($a > b$) at one corner. The remaining area is
A square garden of side $a$ has a square pond of side $b$ ($a > b$) at one corner. The remaining area is
- $(a - b)(a + b)$
- $(a - b)^{2}$
- $(a + b)^{2}$
- $a^{2} - 2ab + b^{2}$
Solution
Remaining area $= a^{2} - b^{2} = (a-b)(a+b)$.
Asked in: IMO
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