A spring of force constant k is cut into lengths of ratio 1 : 2 : 3 . They are connected in series and the…

A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k. If now they are connected in parallel and force constant is k, then k' : k'' is
  1. 1 : 6
  2. 1 : 9
  3. 1 : 11
  4. 1 : 14

Solution

Spring constant 1length
k1l,
Spring constant for the length ratios are k1=6k
k2=3k
k3=2k
In series connection of springs,
1k=16k+13k+12k
1k=66k
k=k.
In parallel connection of springs,
k'=6k+3k+2k
k=11k
kk=111
i.e., k :k=1 :11

Asked in: NEET 2017

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