A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring balance reads $49 \mathrm{~N}$, when the lift is stationary. If the lift moves downward with an acceleration of $5 \mathrm{~m} / \mathrm{s}^2$, the reading of the spring balance will be

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{W}=49 \mathrm{~N} \ & 	herefore \mathrm{m}=\frac{\mathrm{W}}{\mathrm{g}}=\frac{49}{9.8}=5 \mathrm{~kg} \ & \mathrm{~W}^{\prime}=\mathrm{W}-\mathrm{ma}=49-5 	imes 5=49-25 \ & =24 \mathrm{~N}\end{aligned}$ ^

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring…

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