A spinner is divided into $8$ equal sectors numbered $1$ through $8$. Probability of landing on a number…

A spinner is divided into $8$ equal sectors numbered $1$ through $8$. Probability of landing on a number divisible by $3$ is:
  1. $\dfrac{1}{8}$
  2. $\dfrac{1}{4}$
  3. $\dfrac{3}{8}$
  4. $\dfrac{1}{2}$

Solution

Multiples of $3$ in $\{1,2,\ldots,8\}$: $\{3,6\}$ ($2$ numbers). $P = \dfrac{2}{8} = \dfrac{1}{4}$.

Asked in: IMO

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