A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the…


A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object ' O ', is :
( C is the center of curvature of the spherical surface and $R$ is the radius of curvature)
  1. 0.24 m right to the spherical surface
  2. 0.4 m left to the spherical surface
  3. 0.24 m left to the spherical surface
  4. 0.4 m right to the spherical surface

Solution

$\begin{aligned} & \frac{\mu_2}{\mathrm{v}}-\frac{\mu_1}{\mathrm{u}}=\frac{\mu_2-\mu_1}{\mathrm{R}} \\ & \frac{1.5}{\mathrm{v}}-\frac{1}{(-0.2)}=\frac{1.5-1}{0.4} \\ & \frac{1.5}{\mathrm{v}}=\frac{0.5}{0.4}-\frac{1}{0.2} \\ & \frac{1.5}{\mathrm{v}}=-\frac{1.5}{0.4} \\ & \mathrm{v}=-0.4 \mathrm{~m}\end{aligned}$

Asked in: JEE Main 2025 (02 Apr Shift 1)

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