A spherical portion $A$ of radius $R$ is removed from a solid sphere $B$ of radius $2 R$ such that the centre of the removed portion is same as the centre of the sphere $B$. The ratio of the moments of inertia of the remaining spherical shell and the solid sphere B about the axes passing through…

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A spherical portion $A$ of radius $R$ is removed from a solid sphere $B$ of radius $2 R$ such that the centre of the removed portion is same as the centre of the sphere $B$. The ratio of the moments of inertia of the remaining spherical shell and the solid sphere B about the axes passing through their diameters is

Aicharya · Accepted Answer

Angular acceleration, $\alpha=\frac{8}{2}=4 \mathrm{rev} / \mathrm{s}^2$ $\begin{aligned} & \omega_0=0 \ & 	heta=\omega_0 t+\frac{1}{2} \alpha t^2 \ & =0+\frac{1}{2} 	imes 4 	imes 5^2 \ & =50 	imes 2 \pi 	ext { radian, } N=\frac{50 	imes 2 \pi}{2 \pi}=50\end{aligned}$

A spherical portion $A$ of radius $R$ is removed from a solid sphere $B$ of radius $2 R$ such that the…

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