A spherical iron ball of 10 c m radius is coated with a layer of ice of uniform thickness that melts at a rate of 50 c m 3 / m i n . When the thickness of ice is 5 c m , then the rate (in c m / m i n .) at which of the thickness of ice decreases, is:

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Aicharya · Accepted Answer

Let thickness = x &#160; cm Total volume V = 4 3 &#960; 10 + x 3 d V d t = 4 &#960; 10 + x 2 d x d t &#8230; . . ( i ) Given d V d t = 50 &#160; cm 3 / min At x = 5 &#160; cm 50 = 4 &#960; 10 + 5 2 d x d t d x d t = 1 18 &#960; &#160; cm / min

A spherical iron ball of 10 c m radius is coated with a layer of ice of uniform thickness that melts at a…

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