A spherical ball A of mass 4 kg , moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities v 1 m s – 1 and v 2 m s – 1 respectively making angles of 30 ° and 60 ° with respect to the original direction of motion of A .…

Question

A spherical ball A of mass 4 kg , moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities v 1 m s – 1 and v 2 m s – 1 respectively making angles of 30 ° and 60 ° with respect to the original direction of motion of A . The ratio v 1 v 2 will be

Aicharya · Accepted Answer

Applying the law of conservation of linear momentum along a direction perpendicular to the direction of motion (i.e. along the y-axis), we get.

0 + 0 = 4 v_{1} \sin 30 ° - v_{2} \sin 60 °

4 v_{1} \sin 30 ° = v_{2} \sin 60 °

\frac{v_{1}}{v_{2}} = \frac{sin 6 0^{o}}{4 sin 3 0^{o}} = \frac{\sqrt{3}}{4}

A spherical ball A of mass 4 kg , moving along a straight line strikes another spherical ball B of mass 1 kg…

Solution