A sphere of surface area 4   m 2 at temperature 400   K and having emissivity 0 . 5 is located in an environment of temperature 200   K . The net rate of energy exchange of the sphere is (Stefan Boltzmann constant σ = 5 . 67 × 10 - 8   W   m - 2   K 4 )

Question

A sphere of surface area 4 &#160; m 2 at temperature 400 &#160; K and having emissivity 0 . 5 is located in an environment of temperature 200 &#160; K . The net rate of energy exchange of the sphere is (Stefan Boltzmann constant &#963; = 5 . 67 &#215; 10 - 8 &#160; W &#160; m - 2 &#160; K 4 )

Aicharya · Accepted Answer

The net rate of energy exchange of the sphere is, $P = ε σ A [T^{4} - {(T_{s})}^{4}]$ .
Given:
$ε = 0.5$
$σ = 5.67 \times 10^{- 8} W m^{- 2} K^{4}$
$A = 4 m^{2}$
$T = 400 K$ and
$T_{s} = 200 K$
Therefore,
$P = 0.5 \times (5.67 \times 10^{- 8}) \times 4 [400^{4} - 200^{4}] = 2721.6 W$

A sphere of surface area 4   m 2 at temperature 400   K and having emissivity 0 . 5 is located in…

Solution

A sphere of surface area 4 &#160; m 2 at temperature 400 &#160; K and having emissivity 0 . 5 is located in…

Solution

A sphere of surface area 4 m 2 at temperature 400 K and having emissivity 0 . 5 is located in…