A sphere ' $A$ ' of radius ' $R$ ' has a charge ' $Q$,' on it. The field at point $B$ outside the sphere is ' $E$ '. Now another sphere of radius ' $2 R$ ' having a charge ' $-2 Q$ ' is placed at $B$. The total field at the point midway between A and B due to both the spheres is

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Aicharya · Accepted Answer

The field at point ' $B$ ' due to sphere of charge 'Q' will be, $\mathrm{E}=\frac{\mathrm{KQ}}{\mathrm{r}^2}$
Electric field at mid-way between points ' $A$ ' and ' $B$ ' will be, $\begin{aligned} E^{\prime} & =\frac{K Q}{\left(\frac{r}{2}\right)^2}+\frac{K(2 Q)}{\left(\frac{r}{2}\right)^2} \\ & =\frac{4 K Q}{r^2}+\frac{8 \mathrm{KQ}}{r^2} \\ E^{\prime} & =\frac{12 \mathrm{KQ}}{\mathrm{r}^2}=12 \mathrm{E} \end{aligned}$ .

A sphere ' $A$ ' of radius ' $R$ ' has a charge ' $Q$,' on it. The field at point $B$ outside the sphere is…

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