A speech signal of $3 \mathrm{kHz}$ is used to modulate a carrier signal of frequency $1 \mathrm{MHz}$,…
- $1.003 \mathrm{MHz}$ and $0.997 \mathrm{MHz}$
- $3001 \mathrm{kHz}$ and $2997 \mathrm{kHz}$
- $1003 \mathrm{kHz}$ and $1000 \mathrm{kHz}$
- $1.0 \mathrm{MHz}$ and $0.997 \mathrm{MHz}$
Solution
$f_m=3 \mathrm{kHz}=0.003 \mathrm{MHz}$
$\therefore$ Frequency of upper side band $=f_c+f_m$
$=1+0.003=1.003 \mathrm{MHz}$
Frequency of lower side band $=f_c-f_m$
$=1-0.003=0.997 \mathrm{MHz}$
Asked in: AP EAMCET 2020 (22 Sep Shift 2)