A source of unknown frequency gives 4 beats/s when sounded with a source of known frequency $250…

A source of unknown frequency gives 4 beats/s when sounded with a source of known frequency $250 \mathrm{~Hz}$. The second harmonic of the source of unknown frequency gives five beats per second when sounded with a source of frequency $513 \mathrm{~Hz}$. The unknown frequency is
  1. $254 \mathrm{~Hz}$
  2. $246 \mathrm{~Hz}$
  3. $240 \mathrm{~Hz}$
  4. $260 \mathrm{~Hz}$

Solution

Here,
We know beat frequency is the difference of the frequencies of the sources. When unknown source is sounded with known source of frequency 250 Hz, it gives 4 beats/s. It means the frequency of unknown source may be 254 Hz or 246 Hz. Now second harmonic of the source of unknown frequency gives five beats per second, when sounded with a source of frequency 513 Hz. It means the frequency of unknown source may be 518 Hz or 508 Hz.
\(\text {As } \frac{518}{2}=259 \mathrm{~Hz} \text { and } \frac{508}{2}=254 \mathrm{~Hz}\)
Hence unknown frequency is 254 Hz.

Asked in: NEET 2013 (All India)

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