A source of sound is approaching an observer with speed of $30\ \mathrm{ms}^{-1}$ and the observer is…

A source of sound is approaching an observer with speed of $30\ \mathrm{ms}^{-1}$ and the observer is approaching the source with a speed of $50\ \mathrm{ms}^{-1}$. Find the fractional change in the frequency of sound (speed of sound in air = $330\ \mathrm{ms}^{-1}$).

Solution

Sol. Given, $v_s = 30\ \mathrm{ms}^{-1} \Rightarrow v_0 = 50\ \mathrm{ms}^{-1}$ Apparent frequency, $f' = f \left[\frac{v + v_0}{v - v_s}\right]$ $\Rightarrow f' = f \left[\frac{330 + 50}{330 - 30}\right]$ $\Rightarrow f' = f \left[\frac{380}{300}\right]$ $\Rightarrow f' = f \left[\frac{38}{30}\right]$ \nTherefore fractional change in frequency, $\left(\frac{f' - f}{f}\right) = \frac{38 - 30}{30} = \frac{8}{30} = \frac{4}{15}$ Answer: $\frac{4}{15}$

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