A source is stationary and the observer is in motion along a line joining the source and the observer. If the frequency heard by the observer is 1 % higher than the true frequency, the ratio of velocity of the observer and that of sound in air is:

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Aicharya · Accepted Answer

As source is stationary and the observer is moving with velocity $v_{o}$

Let velocity of sound $v$

Observed frequency $(f)$ in Doppler effect is given by

$f = \frac{(v + v_{o})}{v} f_{o}$ Here $f = 1.01 f_{o}$ (Given)

$\Rightarrow 1.01 f_{o} = \frac{(v + v_{o})}{v} f_{o} \Rightarrow \frac{101}{100} = \frac{(v + v_{o})}{v} \Rightarrow \frac{v_{o}}{v} = \frac{1}{100}$

A source is stationary and the observer is in motion along a line joining the source and the observer. If…

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