A source $\mathrm{S}_1$ is producing, $10^{15}$ photons/s of wavelength $5000 Å$. Another source $S_2$ is producing $1.02 imes 10^{15}$ photons per second of wavelength $5100 Å$. Then, (power of $\left.S_2 ight) /\left( ight.$ power of $S_1$ ) is equal to

Question

A source $\mathrm{S}_1$ is producing, $10^{15}$ photons/s of wavelength $5000 Å$. Another source $S_2$ is producing $1.02 	imes 10^{15}$ photons per second of wavelength $5100 Å$. Then, (power of $\left.S_2ight) /\left(ight.$ power of $S_1$ ) is equal to

Aicharya · Accepted Answer

Number of photons emitted per second $\begin{array}{cc} \quad \mathrm{n}=\frac{\mathrm{P}}{\left(\frac{\mathrm{hc}}{\lambda}ight)} \ 	herefore \quad \mathrm{P}=\frac{\mathrm{nhc}}{\lambda} \ \Rightarrow \frac{\mathrm{P}_2}{\mathrm{P}_1}=\frac{\mathrm{n}_2 \lambda_1}{\mathrm{n}_1 \lambda_2}=\frac{1.02 	imes 10^{15} 	imes 5000}{10^{15} 	imes 5100}=1 \end{array}$

A source $\mathrm{S}_1$ is producing, $10^{15}$ photons/s of wavelength $5000 Å$. Another source $S_2$ is…

Solution