A sound wave of frequency $160 \mathrm{~Hz}$ has velocity of $320 \mathrm{~m} / \mathrm{s}$. when it travels through air, the particles having a phase difference of $90^{\circ}$, are separated by a distance of

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{f}=160 \mathrm{~Hz}, \mathrm{v}=320 \mathrm{~m} / \mathrm{s} \ & \lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{320}{160}=2 \mathrm{~m}=200 \mathrm{~cm} \end{aligned}$ Phase difference $\phi=\frac{2 \pi x}{\lambda}$ $\begin{aligned} & 	herefore \mathrm{x}=\frac{\phi \lambda}{2 \pi} \ & =\frac{\pi}{2} \cdot \frac{\lambda}{2 \pi} \quad\left[\because \phi=\frac{\pi}{2}ight] \ & =\frac{\lambda}{4}=\frac{200}{4}=50 \mathrm{~cm} \end{aligned}$

A sound wave of frequency $160 \mathrm{~Hz}$ has velocity of $320 \mathrm{~m} / \mathrm{s}$. when it travels…

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