A sound has an intensity of $2 \times 10^{-8} \text{ Wm}^{-2}$. Its intensity level in decibels is (Take ,…
A sound has an intensity of $2 \times 10^{-8} \text{ Wm}^{-2}$. Its intensity level in decibels is (Take , $\log_{10} 2 = 0.3$)
- 23
- 4.3
- 43
- None of these
Solution
Intensity level (in dB) $= 10 \log_{10} \left(\frac{I}{I_0}\right)$
Here, $I_0 = 10^{-12} \text{ Wm}^{-2}$
$\therefore \text{Intensity level} = 10 \log_{10} \frac{2 \times 10^{-8}}{10^{-12}}$
$= 10(4.3) = 43\text{ dB}$
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