A sound absorber attenuates the sound level by $20\text{ dB}$. The intensity decreases by a factor of

A sound absorber attenuates the sound level by $20\text{ dB}$. The intensity decreases by a factor of
  1. 1000
  2. 10000
  3. 10
  4. 100

Solution

We know that, $\beta = 10 \log \left(\frac{I}{I_0}\right)$ $\Rightarrow \beta_1 = 10 \log \left(\frac{I_1}{I_0}\right)$

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