A sound absorber attenuates the sound level by $20\text{ dB}$. The intensity decreases by a factor of
A sound absorber attenuates the sound level by $20\text{ dB}$. The intensity decreases by a factor of
- 1000
- 10000
- 10
- 100
Solution
We know that, $\beta = 10 \log \left(\frac{I}{I_0}\right)$
$\Rightarrow \beta_1 = 10 \log \left(\frac{I_1}{I_0}\right)$
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