A solution was prepared by dissolving 0.1 mole of a nonvolatile solute in 0.9 moles of water. What is the…

A solution was prepared by dissolving 0.1 mole of a nonvolatile solute in 0.9 moles of water. What is the relative lowering of vapour pressure of solution?
  1. 0.9
  2. 0.5
  3. 0.1
  4. 0.05

Solution

Relative lowering of vapour pressure $=\frac{\Delta \mathrm{P}}{\mathrm{P}}$ $\begin{aligned} & \therefore \quad \frac{\Delta \mathrm{P}}{\mathrm{P}}=\chi_{\text {solute }} \\ & \frac{\Delta \mathrm{P}}{\mathrm{P}}=\frac{\mathrm{n}_{\text {solute }}}{\mathrm{n}_{\text {solute }}+\mathrm{n}_{\text {solvent }}}=\frac{0.1}{0.1+0.9}=\frac{0.1}{1} \\ & \therefore \quad \frac{\Delta \mathrm{P}}{\mathrm{P}}=0.1 \end{aligned}$

Asked in: AP EAMCET 2024 (21 May Shift 1)

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