A solution of Fe 2 SO 4 3 is electrolyzed for ' x ' min with a current of 1 . 5   A to deposit…

A solution of Fe2SO43 is electrolyzed for 'x' min with a current of 1.5 A to deposit 0.3482 g of Fe. The value of x is - [nearest integer]

Given : 1 F=96500 Cmol-1. Atomic mass of Fe=56 gmol-1

Solution

Fe2SO432Fe

w=Zit

w=E96500 it

0.3482=563×96500×1.5×t

t=1200 sec=20 min

Asked in: JEE Main 2022 (25 Jun Shift 2)

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